59 lines
1.7 KiB
Python
59 lines
1.7 KiB
Python
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# -*- coding: utf-8 -*-
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from __future__ import unicode_literals
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"""
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标调位置
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有 ɑ 不放过，
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没 ɑ 找 o、e；
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ɑ、o、e、i、u、ü
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标调就按这顺序；
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i、u 若是连在一起，
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谁在后面就标谁。
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http://www.hwjyw.com/resource/content/2010/06/04/8183.shtml
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https://www.zhihu.com/question/23655297
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https://github.com/mozillazg/python-pinyin/issues/160
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http://www.pinyin.info/rules/where.html
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"""
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# TODO: 增加测试用例：使用 pinyin_dict 中的数据收集所有带声调拼音测试这个规则的正确性
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# 1. 收集所有带声调拼音
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# 2. 转换为数字声调拼音(tone3)，然后再转换为声调拼音
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# 3. 比对转换后的声调拼音跟原始拼音，确保结果一致
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def right_mark_index(pinyin_no_tone):
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# 'iou', 'uei', 'uen': 还原原始韵母后，还需要按照还原前的声调进行标记
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if 'iou' in pinyin_no_tone:
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return pinyin_no_tone.index('u')
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if 'uei' in pinyin_no_tone:
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return pinyin_no_tone.index('i')
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if 'uen' in pinyin_no_tone:
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return pinyin_no_tone.index('u')
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# 有 ɑ 不放过, 没 ɑ 找 o、e
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for c in ['a', 'o', 'e']:
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if c in pinyin_no_tone:
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return pinyin_no_tone.index(c) + len(c) - 1
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# i、u 若是连在一起，谁在后面就标谁
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for c in ['iu', 'ui']:
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if c in pinyin_no_tone:
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return pinyin_no_tone.index(c) + len(c) - 1
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# ɑ、o、e、i、u、ü
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for c in ['i', 'u', 'v', 'ü']:
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if c in pinyin_no_tone:
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return pinyin_no_tone.index(c) + len(c) - 1
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# n, m, ê
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for c in ['n', 'm', 'ê']:
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if c in pinyin_no_tone:
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return pinyin_no_tone.index(c) + len(c) - 1
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